<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom"><channel><title>Frequency Domain on Mi&amp;Bee Blog</title><link>/en/tags/frequency-domain/</link><description>Recent content in Frequency Domain on Mi&amp;Bee Blog</description><generator>Hugo -- gohugo.io</generator><language>en</language><managingEditor>蓝宝石的傻话</managingEditor><lastBuildDate>Fri, 12 Jun 2026 10:00:00 +0800</lastBuildDate><atom:link href="/en/tags/frequency-domain/rss.xml" rel="self" type="application/rss+xml"/><item><title>Frequency Domain Restoration — Inverse and Wiener Filtering</title><link>/en/posts/physical-world/frequency-domain-restoration/</link><pubDate>Fri, 12 Jun 2026 10:00:00 +0800</pubDate><guid>/en/posts/physical-world/frequency-domain-restoration/</guid><description>&lt;h2 id="why-work-in-the-frequency-domain"&gt;Why Work in the Frequency Domain&lt;/h2&gt;
&lt;p&gt;In the previous post we built the image degradation model: the observed image $g(x,y)$ is the original image $f(x,y)$ convolved with a degradation function $h(x,y)$ and corrupted by additive noise $n(x,y)$:&lt;/p&gt;
$$g(x,y) = h(x,y) * f(x,y) + n(x,y)$$&lt;p&gt;Restoration means: given $g$ and $h$, recover $f$ as closely as possible.&lt;/p&gt;
&lt;p&gt;In the spatial domain, this requires solving a deconvolution problem. Deconvolution is a massive linear system. For a $512 \times 512$ image, you face 260,000 unknowns. Direct solving is practically impossible.&lt;/p&gt;</description></item></channel></rss>